Question

2.38 gm of a metal on treatment with nitric acid and
subsequent ignition gave 3.022 gm of the oxide. Specific heat
of the metal is 0.055, enleulate the exact atomie weight.​

Answer 1

Explanation:

ANSWER

Metal +nirtic acid → Metal nitrate → Metal chloride

2g 2.66g

From principle of chemical equivalence

gm equivalent of metal = gm equivalent of chloride

eq. wt of metal

2g

=

eq wt metal chloride

2.66g

eq wt of metal

2g

=

eq.wt of metal + eq wt of chlorine

2.66g

E

2g

=

E+35.5

2.66

( let eq . wt of metal =E )

(2.66−2)E=2×35.5

E=53.78×2=107.58g

Answer 2

Answer:

Explanation:

ANSWER

Metal +nirtic acid → Metal nitrate → Metal chloride

2g 2.66g

From principle of chemical equivalence

gm equivalent of metal = gm equivalent of chloride

eq. wt of metal

2g

=

eq wt metal chloride

2.66g

eq wt of metal

2g

=

eq.wt of metal + eq wt of chlorine

2.66g

E

2g

=

E+35.5

2.66

( let eq . wt of metal =E )

(2.66−2)E=2×35.5

E=53.78×2=107.58g