Math, asked by parth7841, 1 year ago

2-3b+c ^2 fast exams

Answers

Answered by mysticd
0
Hi ,

I think it may be like this ,

( 2 - 3b + c )²

= [ 2 + ( -3b)² + c ]²

= 2²+(-3b)²+c²+ 2 × 2 ( -3b )+2×(-3b)c+2c×2

= 4 + 9b² + c² - 12b - 6bc + 4c

I hope this helps you.

: )
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