Question

2.3g of na reacts with excess of water to form naoh and hydrogen calculate the volume of hydrogen evolved at stp

Answer 1

Answer:

2Na+2C

2

H

5

−OH→2C

2

H

5

−ONa+H

2

Moles of 46 g Na =

23g/mol

46g

=2mol

2 moles of Na will give 1 mole of hydrogen.

The molecular weight of hydrogen is 2 g/mol.

Thus the quantity of hydrogen gas liberated is 2.0 g or 2.0×10

−3

kg