Question

2-3x-2x^2> or = o solve by algebraic method​

Answer 1

this is the quadratic eqn.

firstly arrange in the original sequence i.e

-2x^2-3x+2=0

(* by -)

2x^2+3x-2=0

a=2,b=3,c=-2

∆=b.b-4ac

=3.3-4(2)(-2)

=9+16

=25

roots are real and unequal

by factorization

2x^2+4x-1x-2=0

2x(x+2)-1(x+2)=0

(2x-1)(x+2)=0