Question

2. 3x- 4y- 1 =0, 4x - 3y- 6=0,find the value of x and y?​

Answer 1

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Step-by-step explanation:

Given,

3x+4y-17=0 & 4x-3y-6=0

By using Cross Multiplication, we get

\begin{gathered} = > \frac{x}{(4)( - 6) - ( - 3)( - 17)} = \frac{y}{( - 17)(4) - ( - 6)(3)} = \frac{1}{(3)( - 3) - (4)(4)} \\ \\ = > \frac{x}{( - 24 - 51)} = \frac{y}{( - 68) + (18)} = \frac{1}{( - 9 - 16)} \\ \\ = > \frac{x}{( - 75)} = \frac{y}{( - 50)} = \frac{1}{( - 25)} \\ \\ = > \frac{x}{3} = \frac{y}{2} = 1 \: (multiplying \: by \: - 25) \\ \\ = > so \: x = 3 \: and \: y = 2\end{gathered}=>(4)(−6)−(−3)(−17)x=(−17)(4)−(−6)(3)y=(3)(−3)−(4)(4)1=>(−24−51)x=(−68)+(18)y=(−9−16)1=>(−75)x=(−50)y=(−25)1=>3x=2y=1(multiplyingby−25)=>sox=3andy=2