Question

(2/3xy^2+xy) (2/3xy^2-3xy) expand ​

Answer 1

Answer:

Step-by-step explanation:

x = (3+ 2√2) and xy = 1

y = 1/x =1/( 3 + 2√2)

=( 3 - 2√2)/(3 + 2√2)(3 -2√2)

=(3 -2√2)/(3² - 2√2²)

=(3 -2√2)/(9 -8)

= 3 -2√2

hence ,

(x + y) = 3 +2√2 + 3 -2√2 = 6

now,

(x² + 3xy + y²) = {(x² + y²) + 3xy }

= { (x + y)² -2xy + 3xy }

= { (x + y)² + xy }

= { ( 6)² + 1}

= 37

similarly ,

(x² -3xy + y²)

= { (x + y)² -2xy -3xy }

={ (x + y)² -5xy }

= { (6)² -5×1 }

= { 36 -5}

= 31

hence ,

(x² +3xy + y²)/(x² -3xy + y²) = 37/31

Answer 2

Answer:

12a^2 b^3 c ^-1/15a^-2 b^5 c ^-3