Question

A cylindrical cistern whose radius is 7cm is partly filled with water. If a conical block of iron whose radius of base is 3.5cm and height is 6cm is wholly immersed in the water, by how much will the water level rise? (use π = 22/7)

Answer 1

The water level will rise=77 cubic centimeter

Step-by-step explanation:

Radius of cone=3.5 cm

Height of cone=6 cm

$\pi=\frac{22}{7}$

Volume of cone=$\frac{1}{3}\pi r^2h$

Where r= Radius of base

h=Vertical height of cone

Using the formula

Volume of iron core=$\frac{1}{3}\times \frac{22}{7}\times (3.5)^2\times 6$

Volume of iron block=$77cm^2$

Volume of water rise=Volume of iron block=77 cubic centimeter

Hence, the water level will rise=77 cubic centimeter

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