Question

2(3y-2) -4(2y-5)=9 solve this equation and check your answer


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Answer 1

Answer:

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$2(3y - 2) - 4(2y - 5) = 9$

$6y - 4 - 8y + 20 = 9$

$- 2y + 16 = 9$

$- 2y = 9 - 16$

$- 2y = - 7$

$y = \frac{7}{2}$

Answer 2

Answer:

The solution of the equation $2(3y-2) -4(2y-5)=9$ will be $\frac{7}{2}$ and also it satisfies the equation.

Step-by-step explanation:

As per the data given in the question,

We have to find the value of the equation and also check the answer,

It is given that,

$2(3y-2) -4(2y-5)=9$

Here, we will use the transposition method:

Now distributing the terms,

=> $6y-4 -8y-20=9$

Add the numbers,

=> $6y+16-8y=9$

Combining the like terms,

=> $-2y+16=9$

Now, transposing $16$ on the right side:

=> $-2y=9-16$

-=> $-2y = -7$

Divide both sides by -2,

=> $y = \frac{7}{2}$

So, the value of y is $\frac{7}{2}$ .

Checking:-

=> $2(3y-2) -4(2y-5)=9$

=> $2(3\times \frac{7}{2}-2) -4(2\times \frac{7}{2}-5)=9$

=> $2(\frac{17}{2}) -4(2)=9$

=> $17 - 16 = 9$

=> $9 = 9$

LHS = RHS