Question

(2×-3y)3 expansion of this

Answer 1

Ans. is (. 2. x. -. 3. y. ). ^. 3
Jk
(2x-3y)^3
= 2x^3-3y^3
= (2*2*2*x*x*x)-(3*3*3*y*y*y)
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Answer 2

${(x - y)}^{3} = {x}^{3} - {y}^{3} - 3xy(x - y)$
So expansion of cube of (2x-3y) ,we get
${(2x - 3y)}^{3} = {(2x)}^{3} - {(3y)}^{3}$
$- 3(2x)(3y)(2x - 3y)$
=>
${(2x - 3y)}^{3} = 8 {x}^{3} - 27 {y}^{3}$
$- 36xy(x - y)$
=>
${(2x - 3y)}^{3} = 8 {x}^{3} - 27 {y}^{3}$
$- 36 {x}^{2} y + 36 {y}^{2} x.$
This is expansion of cube of (2x-3y). Hope it helps you... Mark me as Brainliest.