2+4+6+8+.....+2k=90 then the value of k
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Answered by
36
We are given, 2+4+6+..............+2k = 90
clearly, a = 2
and, d = 2
Let there are n terms,
so, an = 2k
2 + (n-1)2 = 2k
so, 2n = 2k
Hence, n = k ------------------------------------------------(1)
We are also given, sn = 90
so, n(a+2k)/2 = 90
=> k(2+2k)/2 = 90 [Using (1) n = k]
k(k+1) = 90
so, k^2 + k - 90 = 0
Hence, k = -10 or k = 9
k can't be negative
Thus, Answer is k = 9
Answered by
8
Answer: 9
Step-by-step explanation:
2+4+6+8+.....+2k=90
2(1+2+......+k) = 90
2]k(k+1)/2] =90
k² + k - 45 =90
(k+10)(k-9)=0
k=9 0r k= -10
k can only be 9 as it is a count and can't be negative
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