2+4+6+8... nterms find java program
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Answer:
public class SumOfSeries{
public static void main(String args[]){
int n = 20;int sum =0;
for(int i=2;i<=n;i=i+2){
if(i%4==0){ sum=sum-i;}
else{ sum=sum+i;}
}
System.out.println("Sum of series upto " + n + " terms is : " + sum);
}
}
Explanation:
We loop all even number upto n, and then subtract multiples of 4 and add the rest
So everytime the number (i) is a multiple of four, the sum will be decremented by it and otherwise i is added to the sum.
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