Question

2) 4 Find A A 2. - 2 । 0 3 3​

Answer 1

Answer:

$\sf {A}^{2} = \left[</p><p></p><p>\begin{array}{c c c}</p><p></p><p> - 2& 21 &19 \\</p><p></p><p> - 3& 4& 1 \\</p><p></p><p> - 3& 15 & 12\end{array}\right]$

Step-by-step explanation:

$\sf Let \: A = \left[</p><p></p><p>\begin{array}{c c c}</p><p></p><p> 1 & 3 & 4 \\</p><p></p><p> -1 & 2 & 1 \\</p><p></p><p>0 & 3& 3</p><p></p><p>\end{array}</p><p></p><p>\right]$

$\sf A²= A.A = \left[</p><p></p><p>\begin{array}{c c c}</p><p></p><p> 1 & 3 & 4 \\</p><p></p><p> -1 & 2 & 1 \\</p><p></p><p>0 & 3& 3</p><p></p><p>\end{array}</p><p></p><p>\right] \times \left[</p><p></p><p>\begin{array}{c c c}</p><p></p><p> 1 & 3 & 4 \\</p><p></p><p> -1 & 2 & 1 \\</p><p></p><p>0 & 3& 3</p><p></p><p>\end{array}</p><p></p><p>\right]$

$\scriptsize\sf A.A = \left[</p><p></p><p>\begin{array}{c c c}</p><p></p><p> 1 \times 1 + 3( - 1) + 4 \times 0 & 1 \times 3 + 3 \times 2 + 4 \times 3 & 1 \times 4 + 3 \times 1 + 4 \times 3 \\</p><p></p><p> -1 \times 1 + 2 ( - 1) + 1 \times 0& - 1\times 3 + 2 \times 2 + 1 \times 3& - 1 \times 4 + 2 \times 1 + 1 \times 3 \\</p><p></p><p>0 \times 1 + 3( - 1) + 3 \times 0& 0 \times 3 + 3\times 2 + 3 \times 3& 0 \times 4 + 3 \times 1 + 3 \times 3</p><p></p><p>\end{array}</p><p></p><p>\right]$

$\scriptsize\sf A.A = \left[</p><p></p><p>\begin{array}{c c c}</p><p></p><p> 1 - 3+0 & 3 + 6 + 12 & 4 + 3 + 12 \\</p><p></p><p> - 1 - 2 + 0& - 3 + 4+ 3& - 4 + 2 + 3 \\</p><p></p><p>0 - 3+ 0& 0 + 6 +9 & 0 + 3+ 9</p><p>\end{array}</p><p>\right]$

$\scriptsize\sf A.A =</p><p>\left[\begin{array}{c c c}</p><p></p><p> - 2& 21 &19 \\</p><p></p><p> - 3& 4& 1 \\</p><p></p><p> - 3& 15 & 12</p><p></p><p>\end{array}</p><p>\right]$

Answer 2

Answer:

above Answer is correct