Question

2.4 g of magnesium is burnt with excess of o2 gas, the amount of magnesium oxide formed will be (Atomic mass of Mg = 24 u)​

Answer 1

Answer:

(34) The moles of magnesium oxide will be, 0.1 mole and amount of magnesium oxide will be, 4 grams.

Answer 2

4 g of Magnesium Oxide is formed.

Given,

Mass of Magnesium available for reaction = 2.4 g

Mass of Oxygen available for reaction = Excess

The atomic mass of Mg = 24 g

To Find,

The amount of Magnesium Oxide formed

Solution,

The reaction between Magnesium and Oxygen is given as follows -

2Mg + O₂ → 2MgO

Now according to stoichiometry,

2 moles of Magnesium will give 2 moles of Magnesium Oxide

Hence, 1 mole of Magnesium will give 1 mole of Magnesium Oxide

Moles of Mg given = $\frac{Mass of Mg given}{Atomic mass of Mg}$

Moles of Mg given = $\frac{2.4}{24}$

Moles of Mg given = 0.1 mol

Now, 0.1 moles of Magnesium will give 0.1 moles of Magnesium Oxide

Mass of Magnesium Oxide formed = 0.1*(24 + 16)

Mass of Magnesium Oxide formed = 0.1*(40)

Mass of Magnesium Oxide formed = 4 g

Hence, 4 g of Magnesium Oxide is formed.

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