Question

2.4 Two numbers are in the ratio 5:3 If they differ.
by 18, the numbers are​

Answer 1

Answer:

let one number be x and another be y

5x-3y=18

x= 18+3y/5

18+3y/5 -3y = 18

18-12y/5 = 18

18-12y= 90

-12y = 72

y = -6

18-18/5

x= 0

Answer 2

Step-by-step explanation:

Given:-

Two numbers are in the ratio 5:3 If they differ.

Two numbers are in the ratio 5:3 If they differ.by 18.

To find:-

Find the nnumbers?

Solution:-

The ratio of two numbers =5:3

Let they be 5x and 3x

They differ by 18

=>5x-3x=18

=>2x=18

=>x=18/2

=>x=9

Now, 5x=5(9)=45

3x=3(9)=27

Answer:-

The two numbers are 27 and 45

Check:-

Difference=45-27=18

The ratio=45:27

=>45/27

=>(5×9)/(3×9)

=>5/3

=>5:3

Verified✅