Question

2.46 gram of sodium hydroxide are dissolved in water and the solution is made 200 cm cube in A volumetric flaskvalculate molarity of solution

Answer 1

Answer : The molarity of solution is, 0.3075 mole/L

Explanation : Given,

Mass of sodium hydroxide = 2.46 g

Molar mass of sodium hydroxide = 40 g/mole

Volume of solution = $200cm^3=200ml$

Molarity : It is defined as the number of moles of solute present in one liter of solution.

In this question, the solute is sodium hydroxide.

Formula used :

$Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution in ml}}$

$Molarity=\frac{2.46g\times 1000}{40g/mole\times 200ml}=0.3075mole/L$

Therefore, the molarity of solution is, 0.3075 mole/L

Answer 2

Answer: The molarity of the solution is 0.3075 M

Explanation:

Molarity is defined as the number of moles that are present in one liter of solution.  The equation that is used to calculate molarity of the solution is:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of sodium hydroxide = 2.46 g

Molar mass of sodium hydroxide = 40 g/mole

Volume of solution = $200cm^3=200mL$     (Conversion factor: $1cm^3=1mL)$

Putting values in above equation, we get:

$\text{Molarity of the solution}=\frac{2.46\times 1000}{40\times 200}=0.3075M$

Hence, the molarity of the solution is 0.3075 M