2.5×10
−3
(I) Se
O
3
2−
+4
+
BrO
3
−
+5
+H
+
→
SeO
4
2−
+6
+
Br
2
0
+H
2
O
(II)
BrO
3
−
+5
+
AsO
2
−
+3
+H
2
O→
Br
−
−1
+
AsO
4
3−
+5
+H
+
In reaction (II),
gm. eq. of BrO
3
−
= gm. eq. of AsO
2
−
n
BrO
3
−
×6=n
AsO
2
−
×2=
1000
12.5
×
25
1
×2=10
−3
n
BrO
3
−
=
6
10
−3
In reaction (I),
moles of BrO
3
−
consumed =
1000
70
×
60
1
−
6
10
−3
=10
−3
gm eq. of SeO
3
2−
=gm. eq. of BrO
3
−
n
SeO
3
2−
×2=10
−3
×5
n
SeO
3
2−
=2.5×10
−3
The answer of my last previous question..
Answers
Answered by
1
Answer:
2.5×10
−3
(I) Se
O
3
2−
+4
+
BrO
3
−
+5
+H
+
→
SeO
4
2−
+6
+
Br
2
0
+H
2
O
(II)
BrO
3
−
+5
+
AsO
2
−
+3
+H
2
O→
Br
−
−1
+
AsO
4
3−
+5
+H
+
In reaction (II),
gm. eq. of BrO
3
−
= gm. eq. of AsO
2
−
n
BrO
3
−
×6=n
AsO
2
−
×2=
1000
12.5
×
25
1
×2=10
−3
n
BrO
3
−
=
6
10
−3
In reaction (I),
moles of BrO
3
−
consumed =
1000
70
×
60
1
−
6
10
−3
=10
−3
gm eq. of SeO
3
2−
=gm. eq. of BrO
3
−
n
SeO
3
2−
×2=10
−3
×5
n
SeO
3
2−
=2.5×10
−3
Explanation:
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Answered by
5
Answer:
If G Is gravitational constant ,sum of its dimensions is……..?
Explanation:
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