A boy fell in well of 100 meters..he come upwards 10 meters everyday but falls 6 meters at night while he sleeps.how many days does it took to come up?
Answers
Answer:
height of well = 100 feet
in 1 day , the height climbed = 10 feet , height slipped = 6 feet
net height = 10–6 = 4 feet.
4 x 23 days = 92 feet.
on 24 th day he will climb 10 feet and get out of well.
so, number of days = 24days
Step-by-step explanation:
so,
24 days is answer
Given :- A boy fell in well of 100 meters..he come upwards 10 meters everyday but falls 6 meters at night while he sleeps . How many days does it took to come up ?
Solution :-
→ Total height of wall = 100 m
→ Upwards every day = 10 m
→ Falls everyday at night = 6 m .
so,
→ In 1 day actual height he fell = 10 - 6 = 4 m .
then,
→ In 23 days actual height he fell = 23 * 4 = 92 m.
now, next day in morning he again starts .
now,
→ Height of wall left to be fell = 100 - 92 = 8 m .
therefore,
→ Time taken by him to fell left height = (8/10) = (4/5) day .
hence,
→ Total number of days required by boy to come up = 23 + (4/5) = 23(4/5) days ≈ 24 days (Ans.)
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