Math, asked by 783075136i, 7 months ago

(2^-5 ÷ 2^-2) find the value​

Answers

Answered by rp3788287
0

Answer:

 {2}^{ - 3}

Step-by-step explanation:

 {2}^{ - 5}  \div  {2}^{ - 2}  \\ since( {a}^{m}  \div {a}^{n } =  {a}^{m - n} ) \\  = {2}^{ - 5 - ( - 2)}  \\  = {2}^{ - 5  +  2}  \\  =  {2}^{ - 3}

Answered by chetanakhairnar2000
0

Answer:

(2^-5 ÷ 2^-2) = 2^(-3)   OR   0.125

Step-by-step explanation:

Given, (2^-5 ÷ 2^-2) = ?

(2^-5 ÷ 2^-2) = (2^-5 * 2^2)

                     = 2^(-5+2)        -------------{Using [ (a^m * a^n) = a^(m+n) ] property}

                     = 2^(-3)

                     = 0.125

Similar questions