Math, asked by kastanjavra, 16 days ago

(√2 + √5) (√2 - √5) = (√2)2 + ………… - …………… - (……….)2
= ………… - …………
= ………………….

Answers

Answered by mrtumble555
0

Answer:

Step-by-step explanation: the most logical way to is understand how we get the first part of our result and use its logic from there all the way until (....)2 since the pattern will reset to √2.

the first part of our result i.e √2)2 because the square root of 2 comes from either bracket /we must start of with square roots and 2 since we get 2 from the version of the √2 that is not the opposite of the square root of 2 and it is not the version which is 2^2 the square of 2 therefore it must be in between. from there √5 and 5 come after the equals sign on the first row, where  √5 is on the first missing number line and 5 is on the 2nd missing number line since the √5 comes from either √5 in either bracket/when we go from square roots then alternate to the number of the sqaure root e.g if we did get √2 the next number based on this problem would be 2.  based on the pattern after we get the number of the square root, we would alternate to the square root of the number and then combine (√2)2 + √5

-5 together and get √3.288 etc since √2)2 =2.828 etc,√5= 2.236, -5=-3.828 etc

and then we have to do √2)2=√2.8284 since √2=1.4142 etc and that √2)2 is twice as big as the square root of 2 and that  2.8284  is twice as big as 1.4142 etc since it is the square root of 2 timesed by 2.

thus making

(√2 + √5) (√2 - √5) = (√2)2 + √5

-5 - (√2)2

= √-3.28etc - √2.8284  

= -1.68178477 etc + 1.81107703 i=0.12929226 i,  the square root of 4 is not a valid option for the 4th number line since the square root of 4 is 2 and √2.8284 is not 2 thus not the square root of 4.  

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