2÷5×(−3)−1÷6×3÷2+1÷14×2
÷5 solve using the appropriate property
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QUESTION:
2÷5×(−3)−1÷6×3÷2+1÷14×2
÷5 solve using the appropriate property:
SOLUTION:
BY using BODMAS
B = BRACKET
O = OF
D = DIVISION
M = MULTIPLICATION
A= ADDITION
S= SUBTRACTION
By applying this formula
2÷5×(−3)−1÷6×3÷2+1÷14×2÷5
= 2÷(-15)-1÷6×3÷2+1÷14×2÷5
= (-2/15)-(1/6)×(3/2)+(1/14)×(2/5)
= (-2/15)- (1/4)+(1/35)
= (-89/420)
ANSWER
-89/420
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