prove that for any set a and b a-b=a∩b'
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A-B means everything in A except for anything in A∩B
A-B=A∩Bc (A intersect B complement)
pick an element x
let x∈(A-B)
therefore x∈A but x∉B
x∉B means x∈Bc
x∈A and x∈Bc
x∈(A∩Bc)
x∈(A-B)
therefore A-B=A∩Bc
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