Question

2). 50 ml 0.5 M H,SO, is added to 75 ml 0.25 M H2SO4
The molarity of resulting solution is :

(a) 0.38 M
(b) 0.175 M
(c) 0.70 M
(d) 0.35 M​

Answer 1

Answer:

M1V1+M2V2=M3V3

0.5 × 50 × 1000(L) + 0.25 × 75 × 1000(L) = M3×125000

25000 + 18750 =M3 × 125000

M3 = 43750 / 125000

M3 = 0.35 M