Question

2.56 g of sulphur in 100 g of cs2 has depression in freezing point of 0.010c kf = 0.1c (molal)1. Hence atomicity of sulphur in the solution is

Answer 1

given,

mass of sulphur, w = 2.56 g

mass of solvent , W = 100g

depression in freezing point , ∆Tf = 0.01 °C

and Kf = 0.1°C/(molal)

using formula,

$M=\frac{K_f\times w\times1000}{W\times\Delta T_f}$

where M is molar mass of sulphur

= 0.1 × 2.56 × 1000/(0.01 × 100)

= 256g

hence, molar mass of sulphur = 256g/mol

now, atomicity = molar mass/atomic mass

= 256/32 = 8

hence, answer is 8

Answer 2

Answer:here is the answer attached

Explanation: