Question

Vapour density of a metal chloride is 66. its oxide contains 53% metal. the atomic weight pf metal is?

Answer 1

Let wt. of metal oxide = 100gm wt. of metal = 53gm wt. of oxygen = 47gm Equivalent weight of oxygen\[=\frac{\text{wt}\text{. of metal}}{\text{wt}\text{. of oxygen}}\times 8\] \[=\frac{53}{47}\times 8=9.02\] Valency \[=\frac{2\times V.D}{E+35.5}=\frac{2\times 66}{9+35.5}=\frac{132}{44.5}=2.96\approx 3\] \[\therefore \] Atomic weight \[=\text{Equivalent weight}\times \text{Valency}\] \[=9.02\times 3=27.06\]