Question

2^567 - 2^569+ 2^571+ 2^568- 2567 = k.2^567 Find the value of K

Answer 1

Answer:

2^567 - 2^569+ 2^571+ 2^568- 2567 = k.2^567

2^567(1-2²+2⁴+2-1)=2^567(k)

2³=K