Question

the volume of oxygen required for complete combustion of 0.75 mole of​

Answer 1

$\huge\star\underline{\mathtt\red{A}\mathtt\green{N}\mathtt\blue{S}\mathtt\purple{W}\mathtt\orange{E}\mathtt\pink{R}}\star\:$

CH

4

+2O

2

⟶CO

2

+2H

2

O

1 mole CH

4

requires 2×22.4 L O

2

at STP.

0.25 moles CH

4

=0.25×2×22.4

=11.2 L or 11.2 dm

3