Question

2:5gm of, three Ethanoic acid (CH3COOH) dissolved in 75gm of benzene. calculate the molality of solution? ​

Answer 1

Answer:

जिस नज़र से आप इस दुनिया को देखेंगे, ये दुनिया आपको वैसी ही दिखेगी।

Answer 2

The molar mass of ethanoic acid is 2(12)+2(16)+4(1)=60 g/mol. The mass of ethanoic acid is divided with molar mass of ethanoic acid to obtain number of moles of ethanoic acid.

Number of moles of ethanoic acid =

60g/mol

2.5g

=0.04167mol

The mass of benzene is 75 grams or

1000

75

=0.075 kg.

The molality of ethanoic acid in benzene is the ratio of the number of moles of ethanoic acid to the mass of benzene (in kg).

It is

0.075kg

0.04167mol

=0.556m