The angle of a triangle are in the ratio 1:2:3 .Find the angle in radians
sol: let the angle of triangle are A, B andC
Given:A:B:C=1:2:3
Let=A=x, B=2x, C=3x
A+B+C= 180°
x+2x+3x=180°
6x=180°
x=30°
put the value of x
A=x
A= 30°
B=2x
B=2×30= 60°
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Solution -
We Have ,
\begin{gathered} \large \sf{a_{5} +a_{7} = 52}\\ \\ \large \sf{ = a + 4d + a + 6d= 52}\\ \\ \large \sf2a + 10d \: \: - - - (1)\\ \\ \large \sf{a_{11} = a + 10d = 46} \\ \\ \end{gathered}
a
5
+a
7
=52
=a+4d+a+6d=52
2a+10d−−−(1)
a
11
=a+10d=46
♠ Multiplying Both Sides by 2 :
\begin{gathered}\large :\longmapsto\sf 2a + 20d = 92\: \: - - - (2) \\ \end{gathered}
:⟼2a+20d=92−−−(2)
♠ Subtracting (1) From (2) , We get :-
\begin{gathered}\sf10d = 40 \\ \\ \sf d = \cancel{\frac{40}{10} }\\ \\ \purple{ \Large :\longmapsto \underline {\boxed{{\bf d = 4} }}}\end{gathered}
10d=40
d=
10
40
:⟼
d=4
Answered by
1
Answer:
30 degree, 60 degree, 90 degree
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