Question

2х + 5y 4х – 5у 2-3, х + 0, y + 0
= 6;
ху
ху
bx ау
+a+b = 0; bx - ay + 2ab = 0
b
bx
ay
+a2 + b = 0; x+y = 2ab
b
2(ax – by ) + (а + 4b) = 0; 2(bx + ay) + (b —
а
a​

Answer 1

Answer:

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