Question

2√6/2-√3+6√2/√6+√3-8√3/√6+√2

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Answer 1

Answer:

$\frac{ 2\sqrt{6} }{2} - \sqrt{3} + \frac{6 \sqrt{2} }{ \sqrt{6} } + \sqrt{3} - \frac{ 8\sqrt{3} }{ \sqrt{6} } + \sqrt{2}$

$\frac{2 \sqrt{6} }{2} + \frac{6 \sqrt{2} }{ \sqrt{6} } - \frac{8 \sqrt{3} }{ \sqrt{6} }$

$\frac{12 + 12 \sqrt{2} - 16 \sqrt{3} }{2 \sqrt{6} }$

$\frac{4(3 + 3 \sqrt{2} - 4 \sqrt{3}) }{2 \sqrt{6} }$

$\frac{4 \sqrt{6}(3 + 3 \sqrt{2} - 4 \sqrt{3}) }{12}$

$\frac{ \sqrt{6}(3 + 3 \sqrt{2} - 4 \sqrt{3} ) }{3}$