2х + Зу = 7
(а - b) х + (a + b) y = За + b – 2
Answers
Given : 2х + Зу = 7
(а - b) х + (a + b) y = За + b – 2
To find : Solve
Solution:
2х + Зу = 7 multiply by a + b
=> 2(a + b)x + 3(a + b)y = 7a + 7b Eq1
(а - b) х + (a + b) y = За + b – 2 multiply by 3
=> 3(a - b)x + 3(a + b) y = 9a + 3b - 6 Eq2
Eq2 - Eq1
=> (a - 5b) x = 2a - 4b - 6
=> x = (2a - 4b - 6) / (a - 5b )
2х + Зу = 7 multiply by a- b
=> 2(a - b)x + 3(a - b)y = 7a - 7b Eq3
(а - b) х + (a + b) y = За + b – 2 multiply by 2
=> 2(a - b)x + 2(a + b) y = 6a + 2b - 4 Eq4
Eq3 - Eq4
=> ( a - 5b)y = a - 9b + 4
=> y = (a - 9b + 4)/(a - 5b )
Learn More
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Step-by-step explanation:
Given:
To find: Value of x and y
Solution:
Method used: Substitution Method
Step 1: Write eq1 in terms of y
Step 2: Multiply eq 2 by 3 and substitute the value of 3y from eq3
Step 3: Put value of x from eq 4 into eq1
Final answer:
Value of x and y are
respectively.
Hope it helps you.
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