Chemistry, asked by chandreshsk7777, 4 days ago

2.7. Discuss the structure
Ophur dioxide.

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Answered by AyanMaiti558

0

Answer:

SO2 molecule has a bent structure with an O–S–O bond angle of 119°. Sulphur is sp2 hybridised and the lone pair of electrons of sulphur reduces the bond angle from 120° to 119°. In the structure, each oxygen atom is attached to sulphur by an σ and a π bond. ... Both S–O bonds are identical because of resonance

Answered by AnanthakrishnanKB

0

Structure of sulphur dioxide:

(i) The structure of SO2 molecule is V-shape with S−O−S bond angle 119 and bond dissociation enthalpy is 297kJ/mol.

(ii) In SO2, each oxygen atom is bounded to sulphur by a ρ and a π bond and the ρ bonds between S and O are formed by sp² -p overlapping.

(iii) Sulphur in SO2 is sp² hybridised forming three hybrid orbitals. Due to lone pair electrons, bond angle is reduced from 120 to 119.

(iv) One of π bonds is formed by pπ−pπ overlapping while other π bond is formed by pπ−pπ overlap.

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