Question

2.76 gm of silver carbonate(Ag2CO3) on heating gives how much mass of silver?
(Ag-108 gm, O-16 gm)
Ag2CO3 --> 2Ag + CO2 + 1⁄2 O2

Answer 1

2Ag2CO3(s)-----› 4Ag(s) + 2CO2(g) + O2(g)

So, on strongly heating silver carbonate will produce silver.

No of moles of silver carbonate = 2.76 g/ 275.7 = 0.0100

No. of moles of Ag = x g/ 108 =

275.7 g of Ag2CO3 produces 108 x 2 g of Ag.

2.76 g will produce = 108 x 2 x 2.76 / 275.7 = 2.16 g of silver.

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