Question

2.8 g of clacum oxide prepared by heating limestone produced 0.8 g of oxygen . claculate the mass percentage of clacium
Please solve the question fast

Answer 1

Mass % of calcium is

2 CaO →∆ 2 Ca + O2Amount of CaO = 2.8 gAmount of oxygen

= 0.8 g

Amount of Calcium = 2g−% of Calcium

= amount of Caamount of CaO × 100 = 2.02.8 × 100 = 71.4 %

Answer 2

Answer:

the above picture answers the given question hope it helps