2.82 grams of glucose is dissolved in 30 gram of water calculate the molality of the solution
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Answer:
ans 0.0522
Explanation:
the weight of glucose 2.82 grams
no. of molecules n2 = 2.82÷ 180
= 0.01567
no. of molecules of n2 = 30÷18
= 1.667
- 0.01567÷1.667× 1000 ÷18
- 0.0522 molal
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