Question

2.82g of glucose is dissolved in 30g of water,the mole fraction of glucose in the solution is (1)0.01 (2)0.99 (3)0.52 (4)1.66

Answer 1

Answer:

0.01

Explanation:

n(glucose) = 2.82/180

= 0.0156

n(h2o) = 30/18

= 1.66

Now,

Mole fraction of glucose = n(glucose)/ n(glucose)+n(h2o)

=0.0156/0.0156+1.66

=0.0156/1.67

=0.01 (approx.)

Hope it helps.