Question

ײ + 9× + 20 = 0


discriminant nature of the roots
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Answer 1

Answer:

• x^2+9x+20=0
• x^2+4x+5x+20=0
• (x^2+4x)+(5x+20)=0
• x(x+4)+5(x+4)=0
• (x+4)(x+5)=0

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Answer 2

Answer:

$\huge\star\underbrace{\mathtt\red{⫷❥ᴀ᭄} \mathtt\green{n~ }\mathtt\blue{ §} \mathtt\purple{₩}\mathtt\orange{Σ} \mathtt\pink{R⫸}}\star\:$

Step-by-step explanation:

$\huge{\underline{\underline{Given→}}}$

→Equation=x^2+9x+20=0

$\huge{\underline{\underline{To\:Find→}}}$

→Discriminant(D) of the given equation.

$\boxed{<strong><em>→</em></strong><strong><em>D=</em></strong><strong><em>b</em></strong><strong><em>^</em></strong><strong><em>2-4</em></strong><strong><em>a</em></strong><strong><em>c</em></strong>}$

$\huge{\underline{\underline{Answer→}}}$

→x^2+9x+20

→D=b^2-4ac

→D=(9)^2-4(1)(20)

→D=81-(4)20

→D=81-80

→D=1

${\boxed{\boxed{→D=1✔}}}$

☞So the Discriminant(D) of the given equation is 1 which a +ve value, so the equation has two distinct and real roots.

HOPE IT HELPS.