Question

2(a^2+b^2)=a^2+2ab+b^2​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

2$a^{2}$ +2$b^{2}$ = $a^{2}$ +2ab+$b^{2}$

2a^2-a^2 + 2b^2-b^2 =2ab

$a^{2}$ + $b^{2}$ =2ab

$a^{2}$-2ab+$b^{2}$ = 0

$(a-b)^{2}$

(a-b)(a-b)

a-b =0

a=b

hence proved