Question

2(a^2+b^2)=(a+b)^2+(a-b)^2​

Answer 1

Answer:

Step-by-step explanation:

$\bold{2( {a}^{2} + {b}^{2} ) = {(a + b)}^{2} + {(a - b)}^{2} } \\ \bold{ \huge{rhs}} \\ {(a + b)}^{2} + {(a - b)}^{2} \\ {a}^{2} + 2ab + {b}^{2} + {a}^{2} - 2ab + {b}^{2} \\ 2 {a}^{2} + 2 {b}^{2} \\ 2( {a}^{2} + {b}^{2} ) \bold{proved}$