Question

cos2x* cos 2y + sin²(x-y)-sin²(x+y) =cos(2x+2y)



50 point​

Answer 1

$\boxed{Explained\:Answer}$

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cos^2x+cos^2y-2cosx.cosy.cos(x+y)

cos^2x+1-sin^2y-2cosx.cosy.cos(x+y)

1+cos^2x-sin^2y-2cosx.cosy.cos(x+y)

1+cos(x+y).cos(x-y)-2cosx.cosy.cos(x+y)

1+cos(x+y){ cos(x-y)-2cosx.cosy }

1+cos(x+y){ cosx.cosy-sinx.siny-2cosx.cosy }

1+cos(x+y){ -cosx.cosy + sinx.siny }

1-cos(x+y){ cosx.cosy-sinxsiny }

1-cos(x+y).cos(x+y)

1-cos^2(x+y)

sin^2(x+y).

Answer 2

Answer:

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