Math, asked by sahasreddy, 9 months ago

2/a+3/b=2 and 4/a -9/y=-1​

Answers

Answered by ItzAditt007
1

\huge{\mathcal{\blue{\underline{\underline{\pink{HeYa!!!}}}}}}

{\huge{\purple{\mathbb{\bold{ANSWER}}}}}

{\large{\orange{\boxed{\bold{a\:=\:2.}}}}}

{\large{\orange{\boxed{\bold{b\:=\:3.}}}}}

<marquee>Explanation</marquee>

{\large{\blue{\bold{\underline{Given:-}}}}}

▪︎ 2/a + 3/b = 2.

▪︎ 4/a - 9/b = -1.

{\large{\blue{\bold{\underline{Now,}}}}}

▪︎ Let 1/a be x and 1/b be y.

By putting the values in given equations we get,

=》 2x + 3y = 2. ---(1)

=》 4x - 9y = -1. ---(2)

● By Multiplying eq(1) by 2 we get,

=》 2{2x + 3y = 2}

=》 4x + 6y = 4. ---(3)

{\large{\blue{\bold{\underline{Now,}}}}}

▪︎ By subtracting eq(2) from eq(3) we get,

=》 (4x+6y) - (4x-9y) = 4-(-1).

=》 4x+6y-4x+9y = 4+1.

=》 6y+9y = 5.

=》 15y = 5.

=》 y = 5/15.

{\large{\red{\boxed{\bold{=》\:y\:=\:1/3}}}}}

{\large{\blue{\bold{\underline{So,}}}}}

▪︎ By putting the value of y in eq(3) we get,

=》 4x + 6(1/3) = 4.

=》 4x + 2 = 4.

=》 4x = 4-2.

=》 4x = 2.

=》 x = 2/4.

{\large{\red{\boxed{\bold{=》\:x\:=\:1/2.}}}}}

{\large{\blue{\bold{\underline{Also,}}}}}

=》 x = 1/a.

=》 1/2 = 1/a.

{\large{\green{\boxed{\bold{=》\:a\:=\:2.}}}}}

▪︎ And,

=》 y = 1/b

=》 1/3 = 1/b

{\large{\green{\boxed{\bold{=》\:b\:=\:3.}}}}}

Therefore

▪︎ The required value of a is 2.

▪︎ The required value of b is 3.

Hope this will help you if it HELPS then plz mark my answer as BRAINLIEST

And remember to always keep a smile on face:D.

<marquee>✌✌THANKS✌✌</marquee>

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