If x = 4, y = 3 and z = (-2) then find the value of :-
x^2 + y^2 + z^2 + 2xyz
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Answer:Here X = 4,Y=3,Z=-2
=x^2+y^2+z^2+2xyz
=4^2+3^2+(-2)^2+2(4)(3)(-2)
=16+9+4-48
=29-48
=-29
Step-by-step explanation:
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