Question

If x = 4, y = 3 and z = (-2) then find the value of :-
x^2 + y^2 + z^2 + 2xyz​

Answer 1

Answer:

.............

......................

Answer 2

Answer:Here X = 4,Y=3,Z=-2

=x^2+y^2+z^2+2xyz

=4^2+3^2+(-2)^2+2(4)(3)(-2)

=16+9+4-48

=29-48

=-29

Step-by-step explanation: