Question

√ 2 a – 3 find zero of polynomial​

Answer 1

Answer:

1/0 ok tayo ha ha thanks so very very

Answer 2

Step-by-step explanation:

Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

.

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.