Question

2.
A(-5, 2) and B(4, 1). Find the equation of
the locus of point P, which is equidistant
from A and B.​

Answer 1

Step-by-step explanation:

let the point be (x,y)

AP = BP

AP² = BP²

(x+5)² + (y-2)² = (x-4)² + (y-1)²

x² + 25 + 10x + y² + 4 - 4y = x² + 16 - 8x + y² +1 - 2y

18x - 2y + 12 = 0

so , locus of P is a straight line

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