Question

2. A bag contains 5 red, 8 green and 7 white balls.
One ball is drawn at random from the bag.
Find the probability that the ball drawn is ( 1 ) a
white ball or a green ball, (2) neither a green
ball nor a red ball and (3) not a white ball.​

Answer 1

Step-by-step explanation:

Total number of balls=20

1.white balls=7,green balls=8

p(e)=15/20=3/4

2.white ball =7

p(e)=7/20

3.not white =red+green=8+5=13

p(e)=13/20