Question

2.
A ball 'A' is thrown upwards from ground level with a
velocity of 20 ms. Another ball 'B'is thrown downwards
from a height of 40 m with the same speed. Find the height
at which the two balls meet (take g = 10 ms?).​

Answer 1

ANSWER:

H=25M

EXPLANATION:

S=S'+S"

40=20t+5t^2+20t-5t^2

40=40t

t=1sec

s=20(1)+5(1)^2

s=25m from ground