Question

2
A
Bau is thrown vertically
upwards its rustwy s seconda
later the greatest Height reached
by the ball is a (g = 10 m/s²)
- ) :
Antwer
h = 19.6 m/sयह बोली ड्रॉइंग विद करली अपोजिशन एंड सेकंड लेटर द ग्रेट थाई क्रीटेड बाय द बॉल इज ​

Answer 1

Answer:

Correct option is

B

(i) 45 m, (ii) 30 m s

−1

The ball is thrown up and it returns in 6sec,

Time of accent = Time of decent

So, time to reach the highest point =6/2=3s

By 2nd equation of motion

s=ut+

2

1

gt

2

To calculate height, consider motion of the ball from highest point to the ground

H=

2

1

gt

2

=

2

1

×10×3

2

=45 m

To calculate projection velocity, consider motion of the ball from projection to return to the point of projection.

0=ut−

2

1

gt

2

u=10×6/2=30 m/s

Answer 2

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