2. A body of mass 10 kg is dropped to the ground from a height
of 10 metres. The work done by the gravitational force is
(g=9.8 m/sec2)
(A) -490 Joules
(B) +490 Joules
(C) -980 Joules
(D)+980 Joules
Answers
Answered by
2
Answer:
(D) 980 Joules is your answer
Explanation:
W=F.s
=98*10
=980 J.
+ve sign because work is done in the same direction of force acting on object.
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Answered by
2
Option D) +980 joules
Explanation:
Mass=10 kg
Height= 10 m
g= 9.8 m/s
i.e., Work Done= m×g×h
=10×9.8×10
=980 joules(Ans)
(Note:- When you are writing the full form of joules write it with short j.....and when you are writing in S.I. form write it with Capital J)
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