Physics, asked by atharvabaluragi, 10 months ago


2. A boll fall of a table and reaches the ground in 35. Assuming 10 m/s calculate its speed on
reaching the ground and height of the table. (u=0 m/s)​

Answers

Answered by Anonymous
2

Explanation:

Let us take- u=0 (as it is kept on table)

v=v (we have to calculate that)

g=10m/s^2

t=1sec

V=u+gt

=0+10*1

=10m/s

Hieght of table

S=ut+1/2 gt^2

=0*1+1/2*10*1

=5m

Therefore hiegt of table is 5 m

hope it helps u ✌

Answered by virat2020
0

Let us take- u=0 (as it is kept on table)

v=v (we have to calculate that)

g=10m/s^2

t=1sec

V=u+gt

=0+10*1

=10m/s

Hieght of table

S=ut+1/2 gt^2

=0*1+1/2*10*1

=5m

Therefore hiegt of table is 5 m

Hope it helps u.

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