Question

2. A bullet moving with a velocity 100 m/s strikes a
mudwall and penetrates through 0.5 m. What is the
time of journey of the bullet through the mud wall?
A) Is
B)0.IS
reols
D).02s
E) 0.25​

Answer 1

Answer:

option e is the correct answer

Explanation:

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Answer 2

Time of journey of the bullet through the mudwall= 0.01s

Explanation:

According to the given information, the bullet moving with a velocity 100 m/s strikes a mudwall and penetrates through 0.5 m.

Therefore, the initial velocity or the velocity of the projectile is equal to 100 m/s (u)

Also, the bullet penetrates the wall to a distance of 0.5 m. (s)

Now, since the bullet penetrates the mudwall, it comes to rest there after travelling a distance of the mentioned 0.5 m. through it. Therefore the final velocity v of the bullet is equal to 0 m/s.

Therefore, $v^{2} = u^{2} + 2as$, where a is the acceleration of the bullet.

Now, putting the values in the above equation, we get,

$0=100^{2} +2a(0.5) = 10000+a\\= > a= -10000$

Therefore, the acceleration obtained = -10000 m/$s^{2}$

Now, we know that, $v=u+at$

Putting the above values in this equation , we get,

$0=100+(-10000)t\\= > 0=1-100t\\= > 1=100t\\= > t=\frac{1}{100} =0.01s$

Hence, the time of journey of the bullet through the mudwall= 0.01s.

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